![]() We know that prime numbers are numbers that have only 2 factors, 1 and the number itself. There are 50 even numbers and 50 odd numbers from 1 to 100. So, the sum of all odd numbers from 1 to 100 is 2500. S = n/2(first odd number + last odd number) ![]() ![]() There are a total of 50 odd numbers, so n = 50. The sum of all odd numbers from 1 to 100 can be found by using the formula, S = n/2(first odd number + last odd number), where n is the total number of odd numbers from 1 to 100. ![]()
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